Thursday, February 28, 2019

Solving Problems

In this essay, I will earn cardinal problems from our textual matter Elementary and Intermediate Algebra I will solve problem 56 on page 437 and problem 10 on page 444. For my primary problem, I will choose an appropriate variable to helper solve the comparison, for my second equality I will identify the form of the equation I end up with once it is solved. I will as well introduce five math vocabulary words, they are, extraneous, proportion, cross reproduce, and extreme- actor and the will be in bold.Problem tally 56 states To estimate the size of the stop creation on the Keweenaw Peninsula, Conservationists captured, tagged, and released 50 nears. One year later, a random model of 100 bears included only 2 tagged bears. What is the conservationists estimate of the size of the bear population? This is a ratio equation and my variable will be b, b= bear population b =10050 2 2*b= 50*100 cross multiply the extreme-means 2b=5000 b= 5000 2 b= 2500 bears 2500 is the conserv ationists estimation of the bear population. This equation is not an extraneous solution because the denominator does not equal zero.Problem number 10y-1= -3 this problem is a proportion x+3 4 (y-1)*4=(x+3)-(-3) cross multiply the x and y which are the extreme and means 4y-4=-3x-9 distribute the 4 and the -3 4y=-3x-9+4 add 4 to both sides 4y=-3x-5 set out both sides by 4 y= -3 x-5 both of these fractions are in parentheses the x and are outside the () 4 4The linear equation in the form of y=mx+b with the slope of -3,4This essay discussed two problems from our textbook Elementary and Intermediate Algebra. It introduced five vocabulary words to help explain the steps in solving the two problems, those vocab words are extraneous, proportion, cross multiply, and extreme-means. This essay identify the variable in problem one, and identified the form of the equation in problem two.Reference Dugopolski, M. (2012). Elementary and intermediate algebra (4th ed.). mod York, NY McGraw-Hill P ublishing.

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